((1)/(125))^(3x-1)=25^(2x+2)

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Solution for ((1)/(125))^(3x-1)=25^(2x+2) equation: 



((1)/(125))^(3x-1)=25^(2x+2)

We move all terms to the left:

((1)/(125))^(3x-1)-(25^(2x+2))=0



Domain of the equation: 125)^(3x-1)!=0

x∈R



We add all the numbers together, and all the variables

(+1/125)^(3x-1)-(25^(2x+2))=0

We multiply all the terms by the denominator


(+1-((25^(2x+2)))*125)^(3x-1)=0



We calculate terms in parentheses: +(+1-((25^(2x+2)))*125)^(3x-1), so:

+1-((25^(2x+2)))*125)^(3x-1

determiningTheFunctionDomain
-((25^(2x+2)))*125)^(3x+1-1

We add all the numbers together, and all the variables

-((25^(2x+2)))*125)^(3x

Back to the equation:

+(-((25^(2x+2)))*125)^(3x)

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